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12/19/2017 7:20 pm  #1


5-match limit

When a wrestler (with 5 matches) is matched with a wrestler (with 4 matches), then the latter wrestler is the winner by default, since the first wrestler has reached the 5 match limit.  However, the program has the result as a tie.  Can the program determine the higher placer based on this situation?
Also, we had a tournament recently in which several 16-man brackets had pigtail matches. (1)  In the 113 bracket, wrestler A had 4 matches and wrestler B had 5 matches, so the result was a tie for 3rd between wrestler A and wrestler B.  Neither wrestler had a pigtail.  (2)  In the 126 bracket, wrestler A had 4 matches and wrestler B had 5 matches, and the program generated a match for the two wrestlers.  Neither wrestler had a pigtail.

 

12/21/2017 4:50 pm  #2


Re: 5-match limit

Your statement "then the latter wrestler is the winner by default, since the first wrestler has reached the 5 match limit" is not called out in the NHFS or NCAA rule books.  It is one possible interpretation of the stated (5 for NFHS, 6 for NCAA) match limit.

With regard to the pigtail match scenarios, the check box in the "File"/"Ladder/Misc preferences..." window specifically states "Force a tie after 5 competed matches (only when the bracket size is 16 w/o pigtails".

I am therefore moving this to the Suggest Enhancements section of this Forum.  Your request is to add a new feature to the program for selecting what to do when one wrestler has reached the limit when the other has not.  It further requests that the program enforce the 5 match limit for brackets with pigtail matches.  Such a request would then need to also support 8 wrestler brackets.

 

1/27/2018 6:29 pm  #3


Re: 5-match limit

On Page 7 of the 2017-18 NFHS Wrestling Case Manual, it states that '. . . if one wrestler had wrestled in four matches and the other wrestler in five matches, then the wrestler with four matches would be the winner by default."  It also states that if both wrestlers had wrestled in five matches, then both wrestlers would receive points for the lesser place and there would be no winner of the higher place.

     Thread Starter
 

1/27/2018 7:18 pm  #4


Re: 5-match limit

On page 7 of the NFHS Case Manual, this situation is presented.  However, I read your responses to an earlier post (dated Jan 2017) which stated a work-around.  This is exactly what I did.  For each "tie" in the 3rd and 5th place matches, I counted the number of matches of each wrestler (omitting any byes or forfeits).  If one wrestler had less than 5 matches, then that wrestler was declared as the winner and the result was "5-match rule" which the program changed to read as "5-0 match rule".  If both wrestlers had 5 matches, then the result was left as a "tie".  However, both wrestlers were specified as 3rd place or 5th place winners, where both wrestlers are presumed to receive additional points.  According to the Case Manual, both wrestlers should be awarded 4th or 5th place, and receive no additional points.
     I can do the manual count to determine the winner by the 5-match rule and manually change the result.  However, the program should change the "tie" wrestlers to the lesser place in order to accommodate the correct awarding of team points.  For example, a tie for 3rd place should result in both wrestlers awarded 4th place.

     Thread Starter
 

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